# Thread: Rotating the region y=x^2 and y=1 around y=6

1. ## Rotating the region y=x^2 and y=1 around y=6

Hi all,

I've been having difficulty with this problem.

Rotate the region of y=x^2 and y=1 around the line y=6

I have done it a couple times now and the homework website keeps saying that its wrong. I'm just looking to see if anyone sees an error in my work.

So I would integrate pi(-6+x^2)^2 dx from -1 to 1. After working that all out I get 322pi/5 as my final answer. Just looking for some fact checking. Thanks!

2. ## Re: Rotating the region y=x^2 and y=1 around y=6

Using the method of washers and the graph's symmetry ...

$\displaystyle 2\pi \int_0^1 (6-x^2)^2 - (6-1)^2 \, dx$

... try again.