Check to make sure you're using radians. It sounds like you're in degrees.
a) given that A is the root of the equation
arccos(x-1)= square root of x+2
show that 0<A<1
b) use the iterative formula
x(n+1) = 1+cos of the square root of xn +2
sorry, the n+1 and n are supposed to be subscript.
when i tried to do part b, i got 1.998....which is not between 0 and 1 so i must be doing it wrong!
can anyone help?
note that the function is continuous on [0,1]
now and . thus by the intermediate value theorem, there is some such that . this is a root. we choose to be this
use the iterative formula to do what? show that 0 < A < 1?b) use the iterative formula
x(n+1) = 1+cos of the square root of xn +2
sorry, the n+1 and n are supposed to be subscript.