# Math Help - [SOLVED] Quick MC Questions... double checking answers.

1. ## [SOLVED] Quick MC Questions... double checking answers.

I have an online quiz, that I am currently taking and should submit pretty soon.
The answer in bold is the one I chose. If I am wrong, please explain why
Thanks for any input, I appreciate it.
---

1) Let R be the region between the curves y=x^2
and y=2x-(x^2).

To find the area of R, we need to

A) integrate [(x^2)-(2x-x^2)] from 0 to 1
B) integrate [(2x-x^2)-(x^2)] from 0 to 1
C) integrate [(x^2)-(2x-x^2)] from 0 to 2
D) integrate [(2x-x^2)-(x^2)] from 0 to 2

2)Let R be the region bounded by the curves y=(x^2)+3 and y=x, for x in [-1,1].

The area of R is equal to

A) 2
B) 17/3
C) 20/3

3) Let R be the region bounded by the curves x=(y^2) and y=x+5, for y in [-1,2].

Sketch the region, then answer the following question.

The most convenient way to find the area of R is to slice the region...

A) horizontally
B) vertically

2. Originally Posted by daneeyah
I have an online quiz, that I am currently taking and should submit pretty soon.
The answer in bold is the one I chose. If I am wrong, please explain why
Thanks for any input, I appreciate it.
---

1) Let R be the region between the curves y=x^2
and y=2x-(x^2).

To find the area of R, we need to

A) integrate [(x^2)-(2x-x^2)] from 0 to 1
B) integrate [(2x-x^2)-(x^2)] from 0 to 1
C) integrate [(x^2)-(2x-x^2)] from 0 to 2
D) integrate [(2x-x^2)-(x^2)] from 0 to 2

2)Let R be the region bounded by the curves y=(x^2)+3 and y=x, for x in [-1,1].

The area of R is equal to

A) 2
B) 17/3
C) 20/3

3) Let R be the region bounded by the curves x=(y^2) and y=x+5, for y in [-1,2].

Sketch the region, then answer the following question.

The most convenient way to find the area of R is to slice the region...

A) horizontally
B) vertically