find ∫∫ (x^2)(y)dA , where R is the upper half of annulus bounded in between (x^2) +(y^2) = 1 and (x^2) +(y^2) = 4 .. Here's my working , i gt my ans = 62/5 instead of the ans given by the author which is 62/15 .... Is my ans wrong ? .
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wrong picture
Originally Posted by romsek wrong picture sorry , here it is
answer is $\dfrac {62}{15}$ your integral setup is correct you forgot a multiplication of 3 in the denominator
Last edited by romsek; Sep 9th 2016 at 08:00 PM.
Originally Posted by romsek answer is $\dfrac {62}{15}$ your integral setup is correct you forgot a multiplication of 3 in the denominator at where ? why 3 is needed ?
Originally Posted by xl5899 at where ? why 3 is needed ? review your calcs, it's pretty obvious where
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