I'm having trouble remembering how to take the integral of

f(x) = (1 - ax) / bx , where a and b are constants.

Any help would be good.

Thanks,

Brett

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- Apr 24th 2006, 07:57 PMcharps43Integration help
I'm having trouble remembering how to take the integral of

f(x) = (1 - ax) / bx , where a and b are constants.

Any help would be good.

Thanks,

Brett - Apr 24th 2006, 08:21 PMearbothQuote:

Originally Posted by**charps43**

1. Expand the RHS of the equation:

$\displaystyle f(x)=\frac{1-ax}{bx}=\frac{1}{b} \cdot \frac{1}{x} - \frac{ax}{bx}$. Don't forget to simplify the 2nd summand.

$\displaystyle \int \left( \frac{1}{b} \cdot \frac{1}{x} - \frac{a}{b} \right) dx=\frac{1}{b} \cdot \ln(x)- \frac{a}{b} \cdot x + C$

Greetings

EB