Question:
A curve is such that dy/dx = 2x² − 5. Given that the point (3, 8) lies on the curve, find the equation of the curve.
Attempt:
dy/dx = 2x²-5
x = 3
2(3)²-5 = 13
y - y1 = m (x - x1)
y - 8 = 13 (x - 3)
y - 8 = 13x - 39
y = 13x - 39 +8
y = 13x -31