Originally Posted by

**Centara** Okay, so first time on the site. Let's hope this goes well, lol.

The question: Find, correct to the nearest degree,the three angles of the triangle with the given vertices.

The vertices: A(1,0), B(3,6), C(-1,4)

So I tried to start it out. Drew it because visuals rock. Then I found the distances between the points.

AB=$\displaystyle \sqrt{40}$

BC=$\displaystyle \sqrt{20}$

CA=$\displaystyle \sqrt{20}$

That's about as far as I was able to go. Any help is appreciated. Thanks!

~Cen