Hey, I need help with the following problem:
Differentiate the function:
g(x)=ln(x*(x^2 - 1)^1/2)
Thanks!
now this is doable by the chain rule. but it is easier to simplify first
note that $\displaystyle \ln \left[ x (x^2 - 1)^{1/2} \right] = \ln \left[ x (x + 1)^{1/2} (x - 1)^{1/2} \right] = \ln x + \frac 12 \ln (x + 1) + \frac 12 \ln (x - 1)$
now you can differentiate each of those terms, right?