1. ## Limit

l'Hopital's rule needs to be applied. Any help will be greatly appreciated!

$\displaystyle \lim_{x \to \infty}{(x-sinx)(e^{-x^2})}$

2. Thank you for your time. I managed to solve it. I will post the solution once I figure out how to work with the math tag.

3. Originally Posted by hasanbalkan
Thank you for your time. I managed to solve it. I will post the solution once I figure out how to work with the math tag.
See the LaTeX Tutorial here

4. 1. Convert it to the form infinity/infinity and simplify
$\displaystyle \lim_{x \to \infty} \frac {x-sinx}{e^{x^2}}$
2. Take the derivatives
$\displaystyle \lim_{x \to \infty} \frac {1-cosx}{(e^{x^2})(2x)}$
3. Since 1 - cosx is either some constant or zero and the denominator is infinity, there are two cases. Either constant/infinity or zero/infinity both of which equal to zero.

5. Originally Posted by janvdl
See the LaTeX Tutorial here
Thank you janvdl. It is really intuitive. I managed to do it just by looking at other people's postings.