Is it true to say that $\displaystyle \sqrt[\infty]{x} = 1$ ? (Where $\displaystyle x > 0$)
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Originally Posted by janvdl Is it true to say that $\displaystyle \sqrt[\infty]{x} = 1$ ? (Where $\displaystyle x > 0$) I would say it as $\displaystyle \lim_{n \to \infty} \sqrt[n]{x} = 1$ $\displaystyle \infty$ is not a (real) number, so you can't calculate with it directly. -Dan
Originally Posted by topsquark I would say it as $\displaystyle \lim_{n \to \infty} \sqrt[n]{x} = 1$ $\displaystyle \infty$ is not a (real) number, so you can't calculate with it directly. -Dan I thought it might involve a limit. Thanks Topsquark.
Originally Posted by topsquark I would say it as $\displaystyle \lim_{n \to \infty} \sqrt[n]{x} = 1$ $\displaystyle \infty$ is not a (real) number, so you can't calculate with it directly. -Dan Of related interest.
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