# volume of solids of revolution

• Jan 23rd 2008, 06:39 PM
chibiusagi
volume of solids of revolution
A drinking glass has the shape of a truncated cone. IF the internal radii of the base and the top are 3 cm and 4 cm respectively and the depth is 10 cm, find by intergration, its capacity. If the glass is filled with water to a depth of 5 cm, fin the volume of the water.

I have done question related to intergration but only with the actual formula T_T so i can't work this out.
• Jan 23rd 2008, 09:12 PM
Soroban
Hello, chibiusagi!

Quote:

A drinking glass has the shape of a truncated cone.
If the radii of the base and the top are 3 cm and 4 cm respectively
and the depth is 10 cm, (a) find by intergration, its capacity.

(b) If the glass is filled with water to a depth of 5 cm,
find the volume of the water.

Turn the glass 90°; the diagram looks like this:
Code:

|
|          *(10,4)
|      *  |
|  *      |
3 *          |
|          |
|          |
|          |
- - - * - - - - - * - -
|          10

The equation of the line is: . $y \:=\:\frac{1}{10}x + 3$

The region bounded by the line, the x-axis, the y-axis, and $x=10$
. . is revolved about the x-axis.

(a) The total volume is: . $V \;=\;\pi\int^{10}_0\left(\frac{1}{10}x+3\right)^2\ ,dx$

(b) The volume of the water is: . $V \;=\;\pi\int^5_0\left(\frac{1}{10}x+3\right)^2\,dx$