the integral from 3 to 5 of (d/dt(Sqrt(2+1t^4)))dt using the fundamental theorem of calculus.thanks for any help
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Do you actually mean: $\displaystyle \int\left(\frac{d}{dt}\sqrt{2+t^{4}}\right)\;dt$? Wouldn't that be $\displaystyle \sqrt{2+t^{4}}\;+\;C$? That should strike you as a definition of an antiderivative.
Originally Posted by waite3 the integral from 3 to 5 of (d/dt(Sqrt(2+1t^4)))dt using the fundamental theorem of calculus.thanks for any help $\displaystyle \int_3^5 \frac{d}{dt} \sqrt{2 + t^4} ~dt = \sqrt{2 + 5^4} - \sqrt{2 + 3^4}$ -Dan
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