How is the answer $\displaystyle 8\sqrt{2}$? i keep getting 0!
Thanks
Take a look at the graph. Since the integrand is never negative the area can't be 0. (The reason is that the square root of a number is never negative.)
Take a look at the graph. Since the integrand is never negative the area can't be 0. (The reason is that the square root of a number is never negative.)
-Dan
I understand it using a graph but i can't compute it algebraically thou....