$\displaystyle \int^{4\pi}_0 \sqrt{1+cos\;x}\;dx$

How is the answer $\displaystyle 8\sqrt{2}$? i keep getting 0!

Thanks

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- Jan 22nd 2008, 06:06 PMpolymeraseHow is it right? (definate integral)
$\displaystyle \int^{4\pi}_0 \sqrt{1+cos\;x}\;dx$

How is the answer $\displaystyle 8\sqrt{2}$? i keep getting 0!

Thanks - Jan 22nd 2008, 06:16 PMtopsquark
- Jan 22nd 2008, 06:17 PMpolymerase
- Jan 22nd 2008, 06:22 PMtopsquark
- Jan 22nd 2008, 06:32 PMThePerfectHacker