Ok, so maybe I'm just missing something simple here, but I'm trying to take the integral of x^2 e^x^3 so I'm doing it with the tabular method, so I'm trying to integrate e^x^3dx for dv and for some reason I just can't get it to match up. I'm using a u sub for $\displaystyle x^3$ and then du is $\displaystyle 3xdx$ but the original integral, e^x^3dx has no x next to e, so I don't see how I can modify du to match up. Even if you divide by 3 to factor that out, you still have $\displaystyle xdx$ instead of $\displaystyle dx$.