the slope of the line y = x - 3 is 1. thus we want this to be the slope of our normal line. however, the normal line is perpendicular to the tangent line, so the slope of the tangent line at the said point is -1. since it is easier to find the slope of the tangent line, we will do so.

- differentiate the function

- set the derivative equal to -1 and solve for x. this will give you the x-coordinate of the point you want. use it to find the y-coordinate

- when you have the point, use the point slope form:

where and is the point i asked you to find

- solve for y to get the equation of the line

- post your solution so we can check