Help

Thank you

Printable View

- Apr 21st 2006, 09:00 PMaskmemathProof(Rate Of)
Help

Thank you - Apr 23rd 2006, 09:20 PMCaptainBlackQuote:

Originally Posted by**askmemath**

Translating the givens into a set of equations gives (hopefully correctly this time):

$\displaystyle \dot c(t)=\alpha\ a(t).b(t)$ for some rate constant $\displaystyle \alpha$, which we will determin later

$\displaystyle c(t)=90-b(t)$

$\displaystyle c(t)=(50-a(t))*2$

Which may be manipulated to give:

$\displaystyle \dot c(t)=\alpha\ (50-c(t)/2)(90-c(t))$,

which is an ODE of variables seperable type.

(I may continue this when I have a bit more time)

RonL