lim as h -> 0 (6 + h) to the power of 3 subtract 216 divided by h Any help?
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Originally Posted by Hockey_Guy14 lim as h -> 0 (6 + h) to the power of 3 subtract 216 divided by h Any help? This is apparently Expand the cubic: Now simplify: Factor: Cancel: And finally take the limit: Many limits in the "secant form" above can be done by this procedure. -Dan
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