a definite integral, lower limit is 1, upper limit is the squre root of 3, integral is
arctan(1/x) I know how to take the integral of arctan(x), but have no clue how I should go about doing this one, help?
that is not a question you should be asking, for the following reasons:
(1) it is something you should know by heart
(2) if you don't know it by heart, it is a very quick google search, text-page flip, or notebook-page flip away
nevertheless, i shall oblige you...
$\displaystyle \frac d{dx} \arctan u = \frac {u'}{1 + u^2}$ .......where $\displaystyle u$ is a function of $\displaystyle x$, of course