Hello,
On ticbol's advice. splitting them up Need some help please
Thank you
These are all variables seperable type, and are solved by rearranging intoOriginally Posted by askmemath
the form:
$\displaystyle
f(y) \frac{dy}{dx}=g(x)
$,
Then the solution is:
$\displaystyle
\int f(y)\ dy=\int g(x)\ dx
$
For example the first ODE is:
$\displaystyle
(x^2-x-2)\frac{dy}{dx}-y=0
$,
which may be rewritten:
$\displaystyle
\frac{1}{y}\ \frac{dy}{dx}=\frac{1}{x^2-x-2}
$
so the solution is:
$\displaystyle
\int \frac{1}{y}\ dy=\int \frac{1}{x^2-x-2}\ dx
$
RonL
Kinda like "Popocateptl?" (It's an, or rather I should say "He's an," Aztec mountain god with the same name as a volcano. I had to do a verbal report on it in Spanish. Do you realize how long I had to practice saying it before it would trip off my tongue?? )Originally Posted by ThePerfectHacker
Of course, I can't even spell "center" correctly ever since I've been loggin on to these forums. Everybody wants to spell it "centre." (sighs and shakes his head in despair)
-Dan