$\displaystyle Cos x= e^y $ 0<x<pi/2 What is dy/dx in terms of x? Thanks!
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Originally Posted by Linnus $\displaystyle Cos x= e^y $ 0<x<pi/2 What is dy/dx in terms of x? Thanks! you may be thinking about differentiating implicitly, but it is possible to solve for y here $\displaystyle \cos x = e^y \implies y = \ln ( \cos x)$ now, can you differentiate that? Hint: use the chain rule
ah, thanks, i can't believe I overlooked that
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