ok, I'm in calc. concepts and I have two questions. Help with either would be greatly appreciated.

1)

Find an equation for the tangent line to f(x) = [-(6+3x^2)/x)] at (2, -9)

I know that the answer is 3x + 2y = -12 I just can't find it! I shouldn't have any problem finding the actual tan line, it's the derivatibe that I'm having trouble with.

I tried using quotient rule and this is what I got:

(-x)(-6x) - (-1)(6 + 3x^2)

------------------------- =

x^2

6x^2 + 6 + 3x^2

----------------------- =

x^2

9x^2 + 6

---------

x^2

which I don't think is right?

2) Find the derivative of

y = -6 - (1/x)

----------

X + 5

yikes! We don't have anything like this in the text, he just kind of snuck it in on the test and I'm trying to figure it out. The answer is:

6x^2 + 2x + 5

--------------

x^2(x+5)^2