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- January 15th 2008, 06:21 AM #1

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- Sep 2007
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- 94

## I want to see if I'm right...

I am given the series (e^n)/(3^(n-1))...Don't forget the Riemann sum symbol in front of this. It appears to be a geometric series. This would mean its ar^n

and a = 1/3 and r = e. I then do a bit of manipulation and get 1/3-1/3(e^n) and then Sn = (1-e^n)/(3-3e)

since r>1, the sequence {r^n} is divergent. Lim n--> infinity Sn does not exist. The geometric series is divergent.

- January 15th 2008, 06:39 AM #2

- January 15th 2008, 07:37 AM #3

- January 15th 2008, 05:02 PM #4

- Joined
- Sep 2007
- Posts
- 94

I have another question. I have to find a telescoping sum of ln n/(n+1). I do not see how to do a partial fraction decomposition on this. Do I have to take the derivative of this expression? I have to find if this expression is convergent and if it is, to find its sum.

- January 15th 2008, 05:06 PM #5