if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a? thanks for the help
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Originally Posted by miley_22 if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a? thanks for the help Partition $\displaystyle [0,a]$ into equal subintervals with width $\displaystyle \frac{a}{n}$. Now from the Riemann sum.
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