# approximate area

• Jan 7th 2008, 03:39 PM
miley_22
approximate area
if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a?

thanks for the help
• Jan 7th 2008, 04:57 PM
ThePerfectHacker
Quote:

Originally Posted by miley_22
if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a?

thanks for the help

Partition $[0,a]$ into equal subintervals with width $\frac{a}{n}$. Now from the Riemann sum.