approximate area

if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a?

thanks for the help

Quote:

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Originally Posted by miley_22

if the formula for the area under a curve with interval 0,1 is 1/n [(1/n)^2+ (2/n)^2+⋯+(n/n)^2 ], then what is the formula for interval 0,a?

thanks for the help

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Partition into equal subintervals with width . Now from the Riemann sum.