1. ## simple integral

Ive totally forgot how to integrate and need help with integrating
3x^2-2 / x with steps shown please my exams on friday and im brickin it

2. $\int {\frac{{3x^2 - 2}}
{x}\,dx} = \int {3x\,dx} - 2\int {\frac{1}
{x}\,dx} .$

Does that make sense?

3. Originally Posted by Krizalid
$\int {\frac{{3x^2 - 2}}
{x}\,dx} = \int {3x\,dx} - 2\int {\frac{1}
{x}\,dx} .$

Does that make sense?
some does, but i dont understand where the 2 over x goes?

4. Originally Posted by jackman
some does, but i dont understand where the 2 over x goes?
did you mean $\int \frac {3x^2 - 2}x~dx$ or $\int \left( 3x^2 - \frac 2x \right)~dx$ ?

Krizalid changed $\int \frac 2x~dx$ to $2 \int \frac 1x~dx$. which is valid. you should know this