Can anyone help me at all?
I have a couple of questions regarding intergration and differentiation that i am stuck on.
1) Differentiation question:-
Find the values of 'x' for which the gradient of the curve y=3+4x-x^2
is equal to a) -1
I started this and got to dy/dx = 4-2x then stuck help!
2) Integration question:-
Integrate with respect to 'x'
a) 1 divided by the square root of 'x' (1/sqrt 'x')
Please feel free to explain your answers as i would like to learn/understand the method of solving involved.
ok so the gradient of the curve at the points you mention just mean to find the tangent line at those line. To find tangent line, you use its derivative.
So, , .
Then you just set the derivative equal to each of the three points and so for x. You should get .
. Let , then .
. Back sub and your done.