lim x^3-1 / x-1 x->1 the answer is 3 lim 3-x / x^2-2x-8 x->4- the answer is + infinit
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$\displaystyle x^3-1 = (x-1)(x^2+x+1)$ $\displaystyle x^2-2x-8 = (x-4)(x+2)$ Try to solve them now.
Originally Posted by wutever lim x^3-1 / x-1 x->1 the answer is 3 1. $\displaystyle \lim_{x \rightarrow 1} \frac{x^3 - 1}{x - 1}$ $\displaystyle \lim_{x \rightarrow 1} \frac{(x - 1)(x^2 + x + 1)}{x - 1}$ $\displaystyle \lim_{x \rightarrow 1} x^2 + x + 1$ $\displaystyle = 3$
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