$\displaystyle \int \frac{x^3}{(x+1)^{10}}\:dx$ Thanks
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Originally Posted by polymerase $\displaystyle \int \frac{x^3}{(x+1)^{10}}\:dx$ The substitution $\displaystyle u=x+1$ does make sense to you?
Originally Posted by Krizalid The substitution $\displaystyle u=x+1$ does make sense to you? but then what do you do at $\displaystyle \int \frac{(u-1)^3}{u^{10}}$?
$\displaystyle (u-1)^3=u^3-3u^2+3u-1.$ Now split the original fraction into four ratios.
Originally Posted by Krizalid $\displaystyle (u-1)^3=u^3-3u^2+3u-1.$ Now split the original fraction into four ratios. Thanks never had to resub so early....
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