The average value of the function f(x) = (x-1)^2 on the interval from x=1 to x=5 is: a) -16/3 b) 16/3 c) 64/3 d) 66/3 e) 256/3
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Originally Posted by DINOCALC09 The average value of the function f(x) = (x-1)^2 on the interval from x=1 to x=5 is: a) -16/3 b) 16/3 c) 64/3 d) 66/3 e) 256/3 Integrate the function and then divide by four. Divide that total area by four to get the average value of 16/3.
Originally Posted by DINOCALC09 The average value of the function f(x) = (x-1)^2 on the interval from x=1 to x=5 is: a) -16/3 b) 16/3 c) 64/3 d) 66/3 e) 256/3 I think (b)
why did they divide by 4? and how do they know what to integrate? Definition: Let be an integrable function on the closed interval . Then the average value of on is given by:
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