The average value of the function f(x) = (x-1)^2 on the interval from x=1 to x=5 is:

a) -16/3

b) 16/3

c) 64/3

d) 66/3

e) 256/3

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- Dec 26th 2007, 10:29 AMDINOCALC09average value
The average value of the function f(x) = (x-1)^2 on the interval from x=1 to x=5 is:

a) -16/3

b) 16/3

c) 64/3

d) 66/3

e) 256/3 - Dec 26th 2007, 10:34 AMcolby2152
- Dec 26th 2007, 10:41 AMIsomorphism
- Dec 26th 2007, 01:36 PMJhevon
why did they divide by 4? and how do they know what to integrate?

**Definition:**Let be an integrable function on the closed interval . Then the average value of on is given by: