The slope of the line tangent to the graph of 3x^2 + 5ln(y) = 12 at (2,1) is... a) -12/5 b) 12/5 c) 5/12 d) 12 e) -7 **Im not particularly differentiating y in respect to x and could use some help.
Follow Math Help Forum on Facebook and Google+
Originally Posted by DINOCALC09 The slope of the line tangent to the graph of 3x^2 + 5ln(y) = 12 at (2,1) is... a) -12/5 b) 12/5 c) 5/12 d) 12 e) -7 **Im not particularly differentiating y in respect to x and could use some help. how else would you do it? i'd differentiate implicitly here and then plug in x = 2, y = 1 into the formula i get. differentiating implicitly we get: now solve for dy/dx and plug in the required x- and y-values
Originally Posted by Jhevon how else would you do it? i'd differentiate implicitly here and then plug in x = 2, y = 1 into the formula i get. differentiating implicitly we get: now solve for dy/dx and plug in the required x- and y-values dy/dx = -6x/(5/y)?
Originally Posted by DINOCALC09 dy/dx = -6x/(5/y)? no. ........move the 6x to the other side by subtracting it from both sides ........multiply both sides by
so as im understanding, the answer is (A) or -12/5
Originally Posted by DINOCALC09 so as im understanding, the answer is (A) or -12/5 yes
View Tag Cloud