Thank you in advance for help with this.

If x = sin θ and y = sec θ, find dy/dx in terms of sin θ and cos θ

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- April 9th 2006, 09:19 PMKiwigirlUsing differentiation to solve problems
Thank you in advance for help with this.

If x = sin θ and y = sec θ, find dy/dx in terms of sin θ and cos θ - April 9th 2006, 11:00 PMrgep
If y and x are both functions of a variable t then dy/dx is (dy/dt) / (dx/dt): that is, it is the quotient of the two derivatives. In this case x = sin t and y = sec t, so dx/dt is cos t and y is 1/cos t, so dy/dt is sin t/cos^2 t (by the chain rule). So dy/dx is sin t/cos^3 t.

- April 12th 2006, 02:27 PMKiwigirl
Thank you rgep for your help!