I don't understand how to grasp such a concept. Obviously the answer is in a+bi form, but I have no idea how to get there. :(

ln(-.3675)

ln(-13.4)

Here are a few problems from my book, can anyone guide me through?

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- Dec 18th 2007, 04:26 PMFailbaitNatural log of a negative number
I don't understand how to grasp such a concept. Obviously the answer is in a+bi form, but I have no idea how to get there. :(

ln(-.3675)

ln(-13.4)

Here are a few problems from my book, can anyone guide me through? - Dec 18th 2007, 05:05 PMThePerfectHacker
- Dec 18th 2007, 05:24 PMFailbait
ln(-.3675) =

ln(-13.4) =

Do those answers look about right?

Thanks! - Dec 19th 2007, 02:35 AMmr fantastic
- Dec 19th 2007, 04:20 AMwingless

For

This is the same thing as ThePerfectHacker's formula. Remember that mine only works for real numbers.

ln(-.3675) =

ln(-13.4) =

Yes, they're correct. - Dec 19th 2007, 08:33 AMThePerfectHacker
- Dec 19th 2007, 01:42 PMwingless
- Dec 19th 2007, 03:05 PMThePerfectHacker
Yes! Sometimes the formula will work sometimes it does not.

Another thing that breaks down is .

Take for example . :eek:

Complex logarithm.