# Math Help - [SOLVED] Dirivative Help [Quotient Rule]

1. ## [SOLVED] Dirivative Help [Quotient Rule]

$
y=\frac{v^3-2v\sqrt{v}}{v}
$

i've tried various techniques and keep getting something like..
$
=\frac{(3v^2-3v\sqrt{v})-(v^3-2v\sqrt{v})}{v^2}
$

im not sure how to get the answer, but BoB says the answer is
$
y'=\frac{2v-1}{\sqrt{v}}
$

help? maybe you can tell what im doing wrong or what i still need to do

2. ## explanation of how i solved.

sorry, i should of searched more before I posted. but this isn't really a quotient rule problem. it is initially set up like one, but sometimes it is easier to rewrite a quotient first to put it in a simpler form.
see:
$y=\frac{v^3-2v\sqrt{v}}{v}
$

$y=\frac{v^3-2v^\frac{3}{2}}{v}
$

divide out the $v$ to get:
$y=v^2-2v^\frac{1}{2}$

hope i helped someone learn something.