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Math Help - [SOLVED] Dirivative Help [Quotient Rule]

  1. #1
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    [SOLVED] Dirivative Help [Quotient Rule]

    <br />
y=\frac{v^3-2v\sqrt{v}}{v}<br />

    i've tried various techniques and keep getting something like..
    <br />
=\frac{(3v^2-3v\sqrt{v})-(v^3-2v\sqrt{v})}{v^2}<br />
    im not sure how to get the answer, but BoB says the answer is
    <br />
y'=\frac{2v-1}{\sqrt{v}}<br />
    help? maybe you can tell what im doing wrong or what i still need to do
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  2. #2
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    Dec 2007
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    Lightbulb explanation of how i solved.

    sorry, i should of searched more before I posted. but this isn't really a quotient rule problem. it is initially set up like one, but sometimes it is easier to rewrite a quotient first to put it in a simpler form.
    see:
    y=\frac{v^3-2v\sqrt{v}}{v}<br />
    y=\frac{v^3-2v^\frac{3}{2}}{v}<br />

    divide out the v to get:
    y=v^2-2v^\frac{1}{2}

    hope i helped someone learn something.
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