There are a variety of ways to solve this problem...
Integrate both sides..
i'm having trouble with this last problem:
The rate of growth dP/dt of a population of bacteria is proportional to the square root of t, where P is the population size and t is the time in days. (0<=t<=10).
That is:
dP/dt = ksqrt(t) sqrt(t) = square root of t, dunno how to type that out with the keyboard.
The initial size of the population is 500. After 1 day the population has grown to 600. Estimate the population after 7 days.
any help would be greatly appreciated!!!!!
Hello, Mr.Obson!
The rate of growth of a population of bacteria
is proportional to the square root of , where is the population size
and is the time in days. .
The initial size of the population is 500.
After 1 day, the population has grown to 600.
Estimate the population after 7 days.
We are told: .
Integrate: . .[1]
When
When
Substitute into [1]: .
When