Derivative:

$\displaystyle

p(t) = t^-^3 - 3t\sqrt{t^3}

$

Is the square root of t^3 the same as t^1.5?

Integrals(Express the following as limits, don't evaluate):

As 0 goes to 4

$\displaystyle

\int {\( (2x+1)^1^/^3} dx =

$

As 4 goes to 7

$\displaystyle

\int {\(\sqrt{2t} dt =

$