I have to find the nth term of this geometric series, i know the formula but im not sure if i need to simplify my answer.

Formula = tn = ar^(n-1)

a) 4,8,16,32 - this I can simplify and get 2^2 * 2^(n-1) which is 2^(n-1)

b) 6,24,96 - can you simplify this after you get 6 * 4^(n-1)?

c) 128,64,32, - same as above

d) 3,3root3, 9, 9root3... - SAA

e) 8,-4,2,-1 ... SAA

Thanks!