...is
My book says the second derivative of a circle is also
Every time I do it, I get
So what is the 2nd derivative of a circle?
Por favor show some steps or tell me how you did it?
Ty
Editops! wrong secition. This isn't homework.
Hi, obviously you are refering to a circle with the equation
Then the first derivative (using implicite derivation) is
To get the second derivative use quotient rule and chain rule:
Substitute y':
Use the first equation and you'll get:
Actually you have to consider 2 cases:
1. The conditions of the upper hemisphere
2. The conditions of the lower hemisphere