Integral of xsin(x^2)
ok, so the answer is .-.5cox^2
however, when i do integration by parts i get -.5cos(x^2)+(1/2x)Cos(x^2)
i cant seem to figure out what i am doing wrong =/
help please
Integral of xsin(x^2)
ok, so the answer is .-.5cox^2
however, when i do integration by parts i get -.5cos(x^2)+(1/2x)Cos(x^2)
i cant seem to figure out what i am doing wrong =/
help please
What have you set to $\displaystyle u$ and what to $\displaystyle dv$ ?
If $\displaystyle dv=sin(x^2)$, $\displaystyle v$ does not equal $\displaystyle (1/2x)sin(x^2)$, as you have to integrate $\displaystyle dv$ to get $\displaystyle v$.
Also (1/2x)sin(x^2) is ambiguous, it could mean (1/(2x))sin(x^2) or =((1/2)x)sin(x^2)
Integral of xsin(x^2)
ok, so the answer is .-.5cox^2
however, when i do integration by parts i get -.5cos(x^2)+(1/2x)Cos(x^2)
i cant seem to figure out what i am doing wrong =/
help please
Set $\displaystyle u=x^2$
$\displaystyle du=2xdx$
From there, you just integrate $\displaystyle 0.5sin(u)$