
Surface Area
I think I am getting the wrong equation! and I keep going over it and over it and keep getting the same. HELP PLEASE!
Find the area of the surface generated by revolving the following curve about the http://webwork1.math.utah.edu/math12...850965img1.gifaxis:
Area of the surface: .

Are you using the correct formula. In parametrics, revolving about the xaxis, surface area is given by:
$\displaystyle 2{\pi}\int_{0}^{\pi}rsin(t)\cdot\sqrt{r^{2}sin^{2} (t)+r^{2}cos^{2}(t)}dt$
Which reduces to:
$\displaystyle 2{\pi}r^{2}\int_{0}^{\pi}[sin(t)]dt$
Which gives the surface area of a sphere.

Thanks a bunch! I forgot to write down the rsin(t)!!! BAH!(Tmi)