Hi, the question asks for the derivative of Sigma notation (n=0) [(2nx^n) / (2n+1)] Is it just f'(x) = 2(n^2)(x^(n-1))? The second part asks for the integral of the above power series so that F(0) = 0?
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Originally Posted by shogunhd Hi, the question asks for the derivative of Sigma notation (n=0) [(2nx^n) / (2n+1)] Is it just f'(x) = 2(n^2)(x^(n-1))? The second part asks for the integral of the above power series so that F(0) = 0? yes, but don't forget the denominator.. note: A power series can be differentiated/integrated term by term over any closed and bounded interval inside the radius of convergence..
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