Hi,
I am having trouble on finding a tangent to this function at x=0
g(x) = ln (2x+1) - 4e^(-3x)
Plugging in x=0, I get g(x) = -4
I know the slope = y' / x'
Taking the derivative I get a slope of 13.
so y= 13x-4
Is this correct?
Hi,
I am having trouble on finding a tangent to this function at x=0
g(x) = ln (2x+1) - 4e^(-3x)
Plugging in x=0, I get g(x) = -4
I know the slope = y' / x'
Taking the derivative I get a slope of 13.
so y= 13x-4
Is this correct?