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Math Help - Tangent line to graph question

  1. #1
    Junior Member
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    Tangent line to graph question

    Hi,

    I am having trouble on finding a tangent to this function at x=0

    g(x) = ln (2x+1) - 4e^(-3x)

    Plugging in x=0, I get g(x) = -4

    I know the slope = y' / x'

    Taking the derivative I get a slope of 13.

    so y= 13x-4

    Is this correct?
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  2. #2
    MHF Contributor kalagota's Avatar
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    Taguig City, Philippines
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    Quote Originally Posted by shogunhd View Post
    Hi,

    I am having trouble on finding a tangent to this function at x=0

    g(x) = ln (2x+1) - 4e^(-3x)

    Plugging in x=0, I get g(x) = -4

    I know the slope = y' / x'

    Taking the derivative I get a slope of 13.

    so y= 13x-4

    Is this correct?
    check your arithmetic.. the slope is 14..
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