Hi, I am having trouble on finding a tangent to this function at x=0 g(x) = ln (2x+1) - 4e^(-3x) Plugging in x=0, I get g(x) = -4 I know the slope = y' / x' Taking the derivative I get a slope of 13. so y= 13x-4 Is this correct?
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Originally Posted by shogunhd Hi, I am having trouble on finding a tangent to this function at x=0 g(x) = ln (2x+1) - 4e^(-3x) Plugging in x=0, I get g(x) = -4 I know the slope = y' / x' Taking the derivative I get a slope of 13. so y= 13x-4 Is this correct? check your arithmetic.. the slope is 14..
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