Hi,

I am having trouble on finding a tangent to this function at x=0

g(x) = ln (2x+1) - 4e^(-3x)

Plugging in x=0, I get g(x) = -4

I know the slope = y' / x'

Taking the derivative I get a slope of 13.

so y= 13x-4

Is this correct?

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- Dec 10th 2007, 05:41 AMshogunhdTangent line to graph question
Hi,

I am having trouble on finding a tangent to this function at x=0

g(x) = ln (2x+1) - 4e^(-3x)

Plugging in x=0, I get g(x) = -4

I know the slope = y' / x'

Taking the derivative I get a slope of 13.

so y= 13x-4

Is this correct? - Dec 10th 2007, 06:06 AMkalagota