# Determine a Dif EQ

• Dec 9th 2007, 09:33 PM
Auxiliary
Determine a Dif EQ
For each of the following, determine a differential equation (or a system of Dif EQ's), which has the expression of what is below for the general sol'n.

1.) $\displaystyle y=c_1\cos(\sqrt{2}t)+c_2\sin(\sqrt{2}t)$

2.) $\displaystyle y=c_1e^{4t}+c_2te^{4t}$

3.) $\displaystyle \textbf{X}=c_1\left(\begin{array}{r}0\\1 \end{array}\right)e^{-3t}+c_2\left(\begin{array}{r} 1\\0 \end{array}\right)e^{2t}$
• Dec 10th 2007, 05:13 AM
TKHunny

1) Imaginary Solutions?

2) Real, Repeated Solutions?

3) Real, Unequal solutions?
• Dec 10th 2007, 05:15 AM
kalagota
Quote:

Originally Posted by Auxiliary
For each of the following, determine a differential equation (or a system of Dif EQ's), which has the expression of what is below for the general sol'n.

1.) $\displaystyle y=c_1\cos(\sqrt{2}t)+c_2\sin(\sqrt{2}t)$

$\displaystyle \frac{d^2y}{dt^2} + 2y = 0$

Quote:

Originally Posted by Auxiliary
2.) $\displaystyle y=c_1e^{4t}+c_2te^{4t}$

$\displaystyle \frac{d^2y}{dt^2} - 8\frac{dy}{dt} + 16y = 0$
• Dec 10th 2007, 08:45 AM
Auxiliary
Quote:

Originally Posted by kalagota
$\displaystyle \frac{d^2y}{dt^2} + 2y = 0$

$\displaystyle \frac{d^2y}{dt^2} - 8\frac{dy}{dt} + 16y = 0$

Thanks kalagota! How exactly did you come up with those by the way? Was it a trial and error type of deal?
• Dec 10th 2007, 08:52 AM
topsquark
Quote:

Originally Posted by Auxiliary
Thanks kalagota! How exactly did you come up with those by the way? Was it a trial and error type of deal?

Quote:

Originally Posted by kalagota
$\displaystyle \frac{d^2y}{dt^2} + 2y = 0$

Let's turn this around for a moment:

How would you go about solving
$\displaystyle \frac{d^2y}{dt^2} + 2y = 0$

-Dan
• Dec 10th 2007, 01:09 PM
TKHunny
Quote:

Originally Posted by Auxiliary
Thanks kalagota! How exactly did you come up with those by the way? Was it a trial and error type of deal?

Come on, Aux. there are nearly eyeball problems. You simply MUST read up on the characteristic equation. You can't be struggling here or you'll never make it.
• Dec 10th 2007, 01:24 PM
Auxiliary
Heh, I do very well on the exams. In fact, I have an A in this course. This is just the harder practice that I choose to do as well. I see now that it was quite trivial, although the systems one will take some work.

Thanks for the help.