∫∫x^3 y/ 1-y^2 dy dx
x= 0
x=1
y= x^2
y=x
By changing the order of integration show that the value of the integral is 1/16
please could anyone help on this one please!
Hello, duude!
The limits are: .
By changing the order of integration, show that the value of the integral is
The region looks like this:Code:| 1+ - - - - - * | **: | *:: : | *:::* : | *::::* : | *::::* : - **- - - - - + - - | 1
Reversing the limits, we have: .
And the integral is: .
The inner integral is: .
. .
Then we have: .