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Math Help - Easy Integration

  1. #1
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    Easy Integration

    A) Integrate y in terms of x
    dy/dx= 5 + 1/(x^2)

    B) Given y=7 when x=1, find value of y at x=2

    I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code.
    Thanks
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  2. #2
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    Quote Originally Posted by markcantdomaths View Post
    A) Integrate y in terms of x
    dy/dx= 5 + 1/(x^2)

    B) Given y=7 when x=1, find value of y at x=2

    I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code.
    Thanks
    What's the problem?
    dy = \left ( 5 + \frac{1}{x^2} \right )dx

    Integrate this and use the initial condition to set your arbitrary constant.

    -Dan
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  3. #3
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    Oh I totally forgot about the +c bit!
    Thanks
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