1. ## Easy Integration

A) Integrate y in terms of x
$\displaystyle dy/dx= 5 + 1/(x^2)$

B) Given y=7 when x=1, find value of y at x=2

I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code.
Thanks

2. Originally Posted by markcantdomaths
A) Integrate y in terms of x
$\displaystyle dy/dx= 5 + 1/(x^2)$

B) Given y=7 when x=1, find value of y at x=2

I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code.
Thanks
What's the problem?
$\displaystyle dy = \left ( 5 + \frac{1}{x^2} \right )dx$

Integrate this and use the initial condition to set your arbitrary constant.

-Dan

3. Oh I totally forgot about the +c bit!
Thanks