A) Integrate y in terms of x $\displaystyle dy/dx= 5 + 1/(x^2)$ B) Given y=7 when x=1, find value of y at x=2 I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code. Thanks
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Originally Posted by markcantdomaths A) Integrate y in terms of x $\displaystyle dy/dx= 5 + 1/(x^2)$ B) Given y=7 when x=1, find value of y at x=2 I tried to inegrate A but couldn't get it to work when I subbed the values in. Sorry I don't know the code. Thanks What's the problem? $\displaystyle dy = \left ( 5 + \frac{1}{x^2} \right )dx$ Integrate this and use the initial condition to set your arbitrary constant. -Dan
Oh I totally forgot about the +c bit! Thanks
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