find the region by rotating about the y-axis $\displaystyle y=e^{-x^2}~~~x-axis~~~~~x=0~~~~and ~~x=1$ I was thinking $\displaystyle v=2pix\int_{0}^{1}e^{-x^2}$
Last edited by akhayoon; Dec 9th 2007 at 03:25 PM. Reason: typo
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but is that enough to bound the entire region or do I need another function?
You're on the right track, except that x belongs inside the integral. $\displaystyle 2{\pi}\int_{0}^{1}xe^{-x^{2}}dx$
Last edited by galactus; Nov 24th 2008 at 05:38 AM.
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