I'm sorry, let me try to be a little more clear, it's kind of hard with these kinds of questions though, since I don't understand whats really going on and I just kind of try to work out patterns from the solutions of all the other questions I've solved like these

$\displaystyle \frac {|x-1||2x+1|}{(3|x^2+x+1|)} < E $

|2x-1|<5 so that means that I could use 5 instead of this expression

I know they got this from $\displaystyle 0<x<2 $ sweet...

and then they go $\displaystyle |x^2+x+1| > 1$

but where did this come from did they use $\displaystyle |x-1|<1$ again somehow??