Third question of the day... p(x)=INTGRL(a=1, b=SQRROOTx) sin^5T. find DY/DY Normally, I know how to do this problem, but I don't know when a is 1. I've only done them when a is equal to zero
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Originally Posted by Super Mallow Third question of the day... p(x)=INTGRL(a=1, b=SQRROOTx) sin^5T. find DY/DY Normally, I know how to do this problem, but I don't know when a is 1. I've only done them when a is equal to zero Do you mean $\displaystyle p(x) = \int_1^{\sqrt{x}}~sin^5(t)~dt$ and to find $\displaystyle \frac{dp}{dx}$? -Dan
Yes, that's exactly it
Originally Posted by Super Mallow Yes, that's exactly it Use the second fundamental theorem with the chain rule: $\displaystyle \frac d{dx} \int_a^{g(x)}f(t)~dt = f(g(x)) \cdot g'(x)$
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